Something a little bit complex : Finding a cube root without a calculator

As logical continuation, the procedure to find a cube root without a calculator or a personal computer is gointg to be analized and shown. Talking of operations, a cube root is a bit more difficult than a square root. As a result,I would ask you for being patient.
So, let’s go to use the number from the previous post, in other words the number 18872162 in order to find its cube root.


To begin with, the next expression can be set out:




n3 = (10a + b)3 +r = 1000a3 + 300a2b + 30ab2 + b3 + r

Being r the remainder of the cube root
Therefore, the first term 1000a3 is connecting with the first figure we obtain. So, the three central terms from the previous expression are going to be used to find the cube root:
300a2b + 300ab2 + b3 which will be added on the right of the cubic root:






The procedure is quite similar to the one to solve a square root. 
Next, it is given details about:

1) The figures are split up into groups of three from right to left.




The cube root is going to be solved with two decimal positions, so it needs three ceros to obtain every decimal place.




2) The first group on the left is taken which is 18. Then, a number that cubed results 18 is looked for. This result must be as close as possible to 18, by default, and it is substracted to 18.
The number is 2, given that 23= 8.








3) The following group of three figures is placed next to 10, forming 10872.








4) The first term of the three listed on the definition at the beginning is set.









The value that is placed between the parentheses is the one at this moment in the position of the solution, ie 2 ( 'a' in our definition ) :

300 x (2)2 x [ ]

Now, 'b' that is the number between square bracket is necessary to be known.









Removing two zeros the above expression is:

3 x (2)2 x [ ] = 12 x [ ]

Then, 108 from 10872 is taken, and is equalized to the previous expression

108 = 12 x [ ]

The number inside the square brackets is 9, which would be the next figure of the root.
However, here an obstacle can come across as well as in a square root. This little problem is related to the previous test so as to get an aproximate figure, due to the fact that using this figure the result exceeds the number which is going to be substracted. It can be seen in the next step.


4) After the figure,which will be used to test, is obtained, the other two central terms from the definition are proposed.








What was pointed previously is possible to be seen here. That is why 16389 can not be substract to 10872, or colloquially, we have been through. Now we test with 8. 








Testing with 7 is required due to the same problem.








And again the same. Thus the figure has to be 6.








So, it works now .

5Afterwards, the same procedure must be fulfilled again, placing the next group of the decimal numbers next to 1296.














3 x 262 = 2028

¿How many 2028 are there in 12961? 6,391, so the test will be done using 6.













6) The process is fulfilled using the other two groups of figures that remain in order to obtain the cube root with two decimal figures.








































All in all, the cube root of 18872162 with two decimal figures is 266.24 and the remainder would be 75.701376. As it is possible to be seen, the more decimal figures are added the more cumbersome the procedure becomes, but it think that it can be understand properly.



I hope this has been interesting and beneficial for you.

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